Calculate the mass of carbon monoxide (IV) which forms 3 mol of methane upon combustion.

Methane burns in the presence of oxygen to release carbon dioxide and water. The equation for this reaction can be written as follows:

CH4 + 2 O2 = CO2 + 2 H2O

Having studied the reaction equation, you can see that the amount of methane substance is equal to the amount of carbon dioxide. Thus, we get: n (CH4) = n (CO2) = 3 mol.

The molar mass of carbon dioxide is 44 g / mol. We can now find the mass of 3 moles of carbon dioxide:

m = 3 * 44 = 132 g of carbon dioxide was released.

Answer: the mass of carbon monoxide (IV) is 132 g.