Calculate the mass of chloroethane which is formed by the interaction of 4.6 g of ethanol with hydrogen chloride.

Let’s implement the solution:
1. We write down the equation:
С2Н5ОН + НCl = C2H5Cl + H2O – exchange, chloroethane was obtained;
2. Calculations by formulas:
M (C2H5OH) = 46 g / mol.
M (C2H5Cl) = 64.5 g / mol.
3. Determine Y (mol) of ethanol:
Y (C2H5OH) = m / M = 4.6 / 46 = 0.1 mol.
Y (C2H5Cl) = 0.1 mol since the amount of substances is 1 mol according to the equation.
4. Find the mass of the product:
m (C2H5Cl) = Y / M = 0.1 * 64.5 = 6.45 g.
Answer: Ethane chloride weighing 6.45 g was obtained.