Calculate the mass of chloroform that can be obtained from 6.72L of chlorine.

To solve the problem, we write down the equations of the methane chlorination process:
1. CH4 + Cl2 = CH3Cl + HCl;
CH3Cl + Cl2 = CH2Cl2 + HCl;
CH2Cl2 + Cl2 = CHCl3 + HCl;
The substance chloroform – CHCl3 is a product of the substitution reaction.
2. Let’s calculate the molar masses:
M (Cl2) = 71 g / mol;
M (CHCl3) = 121.5 g / mol.
3. Determine the number of moles of CH4, CHCl3:
1 mole of gas at normal level – 22.4 liters;
X mol (Cl2) – 6.72 L. hence, X mol (Cl) = 1 * 6.72 / 22.4 = 0.3 mol;
Y (CHCl3) = 0.3 mol since the amount of these substances according to the equation is 1 mol.
4. Find the mass of the reaction product:
m (CHCl3) = Y * M = 0.3 * 121.5 = 36.45 g.
Answer: the mass of chloroform is 36.45 g.