Calculate the mass of chromium that can be obtained by reducing 380 g of chromium oxide (|||), with a product yield of 48%.

To solve, we write:
1.Cr2O3 + H2 = 2Cr + 3H2O – OBP, chromium obtained;
2. Calculations:
M (Cr2O3) = 151.8 g / mol.
M (Cr) = 51.9 g / mol.
Y (Cr2O3) = m / M = 380 / 151.8 = 2.5 mol.
3. Proportion:
2.5 mol (Cr2O3) – X mol (Cr);
-1 mol -2 mol from here, X mol (Cr) = 2.5 * 2/1 = 5 mol.
4. Find the mass of the product:
m (Cr) = Y * M = 5 * 51.9 = 259.5 g (theoretical weight).
W = m (practical) / m (theoretical) * 100;
m (practical) = 0.48 * 259.5 = 124.6 g.
Answer: the mass of chromium is 124.6 g.