Calculate the mass of CO2 that can be produced by reacting 7g CaCo3. from HCl weighing 30 g

Calculate the mass of CO2 that can be produced by reacting 7g CaCo3. from HCl weighing 30 g., the mass fraction of HCl in which is 20%.

1. Let’s compose the equation of the chemical reaction:

c + 2HCl = CaCl2 + CO2 + H2O.

2. Find the chemical amount of calcium carbonate and hydrochloric acid:

n (CaCO3) = m (CaCO3) / M (CaCO3) = 7 g / 100 g / mol = 0.07 mol.

m (HCl) = m (solution) * ω (HCl) / 100% = 30 g * 20% / 100% = 6 g.

n (HCl) = m (HCl) / M (HCl) = 6 g / 36.5 g / mol = 0.164 mol.

3. Using the reaction equation, we find the chemical amount, and then the mass of carbon monoxide:

! CaCO3 is in short supply.

n (CO2) = n (CO2) = 0.07 mol.

m (CO2) = n (CO2) * M (CO2) = 0.07 mol * 44 g / mol = 3.08 g.

Answer: m (CO2) = 3.08 g.