# Calculate the mass of co2 that will be released if the caco3 limestone was treated with hcl weighing 36.5 g.

Calculate the mass of co2 that will be released if the caco3 limestone was treated with hcl weighing 36.5 g. M (co2) = 44 g / mol. M (HCl) = 36.5 g / mol.

When calcium carbonate interacts with hydrochloric acid, calcium chloride, water and gaseous carbon dioxide are produced. The reaction proceeds according to the following chemical equation:
CaCO3 + 2HCl = CaCl2 + CO2 ↑ + H2O;
Let’s calculate the chemical amount of hydrochloric acid. For this purpose, we divide its weight by its molar weight.
M HCl = 1 + 35.5 = 36.5 grams / mol; N HCl = 36.5 / 36.5 = 1.0 mol;
With 0.5 mol of calcium carbonate, 1.0 mol of hydrochloric acid will react. This will release 0.5 mol of carbon dioxide.
Let’s calculate its weight. To do this, multiply the amount of a substance by its molar weight.
M CO2 = 12 + 16 x 2 = 44 grams / mol; m CO2 = 0.5 x 44 = 22 grams;

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