Calculate the mass of copper and the volume of oxygen required to obtain 8 g of copper oxide (||).

Copper reacts with oxygen to form oxide. The reaction is described by the following chemical reaction equation:

Cu + ½ O2 = CuO ↑;

Let’s calculate the chemical amount of copper oxide. To do this, we divide the mass of the available substance by the weight of 1 mole.

M CuO = 64 + 16 = 80 grams / mol;

N CuO = 8/80 = 0.1 mol;

To get this amount of copper oxide, you need to take the same amount of copper.

Determine the weight of the copper. For this purpose, we multiply the amount of the substance by the weight of 1 mole of the substance.

M Cu = 64 grams / mol;

m Cu = 0.1 x 64 = 6.4 grams;

To obtain such an amount of copper oxide, it is necessary to take 2 times less oxygen.

Let’s calculate the volume of oxygen.

To find the volume of oxygen, we multiply the amount of the substance by the volume of 1 mole of gas (which is 22.4 liters).

m O2 = 0.1 / 2 x 22.4 = 1.12 liters;