Calculate the mass of copper hydroxide formed during the reaction 155 ml. 10% sodium

| June 15, 2021 | education

Calculate the mass of copper hydroxide formed during the reaction 155 ml. 10% sodium hydroxide solution with copper II nitrate solution.

Let us write the reaction equation for the formation of copper hydroxide:

2NaOH + Cu (NO3) 2 = Cu (OH) 2 + 2NaNO3.

It can be seen from the equation that the amount of the starting material is twice the reaction product, which means:

2n (NaOH) = n (Cu (OH) 2).

Find the mass of sodium hydroxide by the formula:

m (NaOH) = V • p • w / 100.

We take the density from the reference data, taking into account the percentage concentration of alkali.

m (NaOH) = 155 * 1.1089 * 10/100 = 17.2 g.

Knowing the mass, we find the number of moles:

n (NaOH) = m / Mr = 17.2 / 40 = 0.4 mol.

Then the number of moles of copper hydroxide is:

n (Cu (OH) 2) = n (NaOH) / 2 = 0.4 / 2 = 0.2 mol.

The mass of the formed hydroxide:

m (Cu (OH) 2) = n • Mr = 0.2 • 98 = 21 g.



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