Calculate the mass of copper hydroxide precipitate 2 obtained by the interaction of 160 grams of 10%

Calculate the mass of copper hydroxide precipitate 2 obtained by the interaction of 160 grams of 10% copper sulfite solution with potassium hydroxide solution

Given:
m p (CuSO3) = 160 g
w (CuSO3) = 10% = 0.1
To find:
m (Cu (OH) 2)
Decision:
CuSO3 + 2KOH = K2SO3 + Cu (OH) 2
m in (CuSO3) = w * m p = 0.1 * 160 g = 16 g
n (CuSO3) = m / M = 16 g / 144 g / mol = 0.1 mol
n (CuSO3): n (Cu (OH) 2) = 1: 1
n (Cu (OH) 2) = 0.1 mol
m (Cu (OH) 2) = n * M = 0.1 mol * 98 g / mol = 9.8 g
Answer: 9.8 g