Calculate the mass of copper oxide that reacts with 250 g of sulfuric acid.

1. Let’s compose the equation:
CuO + H2SO4 = CuSO4 + H2O – ion exchange reaction, copper sulfate was obtained;
2. Let’s make calculations using the formulas:
M (CuO) = 63.5 + 16 = 79.5 g / mol;
M (H2SO4) = 1 * 2 + 32 + 16 * 4 = 128 g / mol;
3. Let’s calculate the number of moles of sulfuric acid by the formula:
Y (H2SO4) = m / M = 250/128 = 1.95 mol;
4. Let’s make the proportion:
1.95 mol (H2SO4) – X mol (CuO);
-1 mol – 1 mol from here, X mol (CuO) = 1.95 * 1/1 = 1.95 mol;
5. Let’s calculate the mass of copper oxide:
M (CuO) = Y * M = 1.95 * 79.5 = 155 g.
Answer: copper oxide weighing 155 g entered into the reaction.