Calculate the mass of copper oxide that will be required to obtain 3 mol by the reaction CuO + H2 = Cu + H2O

univerkov | December 11, 2020 | education

We make the proportion:
x (mol) / 1 (mol) = 3 (mol) / 1 (mol)
Hence x = 3 (mol)
n (CuO) = 3 (mol)
M (CuO) = 16 +64 = 80 (g / mol)
m (CuO) = n * M = 3 (mol) * 80 (g / mol) = 240 (g)

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