Calculate the mass of copper reduced from copper oxide (2) by hydrogen, which is released by the action

Calculate the mass of copper reduced from copper oxide (2) by hydrogen, which is released by the action of hydrochloric acid on zinc with a mass of 245

During this chemical reaction, zinc metal is converted to a zinc chloride salt. Zinc is a divalent metal. Therefore, during the reaction, it interacts with a double amount of hydrochloric acid. In this case, a single molar amount of zinc chloride is synthesized.The reaction proceeds in accordance with the following chemical equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s calculate the chemical amount of zinc. For this purpose, we divide its weight by the mass of 1 mole of metal.

N Zn = 245/65 = 3.77 mol;

With this amount of zinc, 7.54 mol of acid will react. In this case, 3.77 mol of hydrogen will be obtained. With this amount of hydrogen, 3.77 mol of copper oxide can be reduced and 3.77 mol of copper can be obtained.

Let’s determine its weight.

M Cu = 64 x 3.77 = 241.28 grams;