Calculate the mass of copper required to obtain 8 g of copper (II) oxide.

The oxidation reaction of copper with oxygen is described by the following chemical reaction equation:

Cu + ½ O2 = CuO;

1/2 mole of gas is reacted with 1 mole of copper. 1 mol of its oxide is synthesized.

Let’s calculate the available chemical amount of copper oxide substance.

M СuO = 64 + 16 = 80 grams / mol;

N CuO = 8/80 = 0.1 mol;

This reaction requires 0.1 mol of copper.

Let’s calculate its weight.

M Сu = 64 grams / mol;

m Cu = 0.1 x 64 = 6.4 grams;