Calculate the mass of copper sulfate (||), which is formed by interaction with sulfuric acid

Calculate the mass of copper sulfate (||), which is formed by interaction with sulfuric acid, copper oxide (||) weighing 32 g.

Given:

m (CuO) = 32 g

Find:

m (CuSO4) -?

Solution:

CuO + H2SO4 = H2O + CuSO4, – we solve the problem, relying on the composed reaction equation:

1) Find the amount of copper oxide that has reacted:

n (CuO) = m: M = 32 g: 80 g / mol = 0.4 mol

2) We compose a logical expression:

If 1 mol of CuO gives 1 mol of CuSO4,

then 0.4 mol CuO will give x mol CuSO4,

then x = 0.4 mol.

3) Find the mass of copper sulfate formed during the reaction:

m (CuSO4) = n * M = 0.4 mol * 160 g / mol = 64 g.

Answer: m (CuSO4) = 64 g.