Calculate the mass of copper that can be obtained by the interaction of 5.4 g of aluminum with a solution of copper chloride 2

Given:

m (Al) = 5.4 g

To find:

m (Cu) -?

Decision:

3CuCl2 + 2Al = 2AlCl3 + 3Cu, – we solve the problem, relying on the composed reaction equation:

1) Find the amount of aluminum that has reacted:

n (Al) = m: M = 5.4 g: 27 g / mol = 0.2 mol.

2) We make a logical expression: if 3 mol of Cu requires 2 mol of Al, then x mol of Cu requires 0.2 mol of Al, then x = 0.3 mol.

3) Find the mass of copper precipitated as a result of the reaction:

m (Cu) = n * M = 0.3 mol * 64 g / mol = 19.2 g.

Answer: m (Cu) = 19.2 g.