Calculate the mass of copper that can be obtained by the reduction of copper (2) oxide

Calculate the mass of copper that can be obtained by the reduction of copper (2) oxide with a mass of 80 grams with hydrogen.

Given:

m1 (CuO) = 80 g.

Find:

m2 (Cu) =?

Solution:

1) We compose the equation of the chemical reaction:

CuO + H2 = Cu + H2O.

2) The formula for solving the problem: m1: m2 = M1: M2, hence m2 = (m1 x M2): M1.

3) Find the molecular weights using the periodic table:

M1 (CuO) = 64 + 16 = 80 g / mol;

M2 (Cu) = 64 g / mol.

4) 80 g: 80 g / mol = m2: 64 g / mol.

m2 = (80 x 64): 80 = 64 g.

Answer: m2 (Cu) = 64 g.