Calculate the mass of copper that can be reduced with hydrogen from copper (II) oxide weighing 320 g.

Given:

m (CuO) = 320 g;

To find:

m (Cu) -?

Decision:

CuO + H2 = Cu + H2O, – we solve the problem, relying on the composed reaction equation:

1) Find the amount of copper oxide that has reacted:

n (CuO) = m: M = 320 g: 80 g / mol = 4 mol.

2) We compose a logical expression:

If 1 mole of Cu requires 1 mole of CuO,

then x mol Cu requires 4 mol CuO,

then x = 4 mol.

3) Find the mass of copper precipitated as a result of the reaction:

m (Cu) = n * M = 4 mol * 64 g / mol = 256 g.

Answer: m (Cu) = 256 g.