Calculate the mass of copper that will be released when copper oxide interacts with hydrogen with a volume of 6.72 liters.

Let’s write the reaction equation:

CuO + H2 = Cu + H2O

n (H2) = V / Vm = 6.72 / 22.4 = 0.3 mol (n is the number of moles of hydrogen, Vm is the volume of one mole of a substance, the value is constant, equal to 22.4 g / mol);
from n (H2) = 1 mol it turns out n (Cu) = 1 mol (according to the equation, the coefficients in front of the formulas of hydrogen and copper are equal to 1);
m (Cu) = n (Cu) * M (Cu) = 0.3 * 63.5 = 19g .;
M (Cu) = 63.5 g / mol (found from the periodic table);