Calculate the mass of CuSO4 * 5H2O required to prepare 5 liters of a 0.01% solution.

For the calculation, we take the density of the solution equal to 1 gram / cm3. In this case, the mass of the solution will be 5,000 grams.

Let’s find the mass of water salt required to prepare 5 liters of a 0.01% solution.

The solution should contain 5,000 x 0.01 / 100 = 0.5 grams of CuSO4.

Let’s find the amount of the substance.

M CuSO4 = 64 + 32 + 16 x 4 = 160 grams / mol;

N CuSO4 = 0.5 / 160 = 0.003125 mol;

Find the mass 0.003125 mol CuSO4 * 5H2O.

M CuSO4 * 5H2O = 160 + 18 x 5 = 250 grams / mol;

m CuSO4 * 5H2O = 250 x 0.003125 = 0.781 grams;