Calculate the mass of ethanal obtained from acetylene with a volume of 61.6 liters.

To solve, we compose the equation of the process:

С2Н2 + Н2О = Н2С = СНОН (vinyl alcohol) = Н3С – СОН – hydration, ethanal is obtained;
Proportion:
1 mol of gas at normal level – 22.4 liters;

X mol (C2H2) – 61.6 liters from here, X mol (C2H2) = 1 * 61.6 / 22.4 = 2.75 mol;

Y (C2H4O) = 2.75 mol since the amount of substances is 1 mol.

3. Find the mass of the product:

m (C2H4O) = Y * M = 2.75 * 44 = 121 g

Answer: the mass of ethanal was 121 g