Calculate the mass of ethane required to obtain 25 liters of ethylene from the dehydrogenation reaction.

V (C2H4) = 25 l.
Let’s determine the mass of ethane, which is obtained as a result of the reaction. We write down the solution.
C2H4 + H2 = C2H6
First, we find the volume of ethane that is obtained as a result of the reaction. We write down the solution.
25 l ethene – x l ethane
22.4 l / mol ethene – 22.4 l / mol ethane
Find the volume of ethane.
V (C2H6) = 25 * 22.4: 22.4 = 25 liters.
Next, let’s determine the mass of ethane.
n = m / M.
n = V / Vm.
m / M = V / Vm.
m = M * V / Vm.
M (C2H6) = 2 * 12 + 6 * 1 = 30 g / mol.
m = 30 * 25: 22.4 = 33.5 g.
The mass of the ethane obtained is 33.5 g.
Answer: the mass of ethane is 33.5 g.