Calculate the mass of ethanol and potassium that have reacted to give 56 ml of hydrogen.
| December 10, 2020 | education
2C2H5OH + 2K = 2C2H5OK + H2
56 ml = 0.056 l
n (H2) = 0.056 / 22.4 = 2.5 * 10 ^ -3 mol
n (c2h5oh) = n (k) = n (h2) * 2 = 0.005 mol
m (c2h5oh) = 0.005 * 46 = 0.23g
m (k) = 0.005 * 39 = 0.195g
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