Calculate the mass of ethanol that can be obtained by the interaction of 40 g of ethene with water.

univerkov | November 26, 2020 | education

CH2 = CH2 + H2O -> C2H5OH M (CH2 = CH2) = 28 g / mol
m (CH2 = CH2) = 40 g n = 40/28 = 1.43 mol
Then the mass of ethanol will be m (C2H5OH) = 1.43 * 46. = 65.8 g

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