Calculate the mass of ethanol, the yield of which is 70%, obtained by hydration of 5.6 liters of ethylene.

Reaction equation:

C2H4 + H2O (t, P, cat.) = C2H5OH

Let’s find the amount of substance C2H4:

v (C2H4) = V (C2H4) / Vm = 5.6 / 22.4 = 0.25 (mol).

According to the reaction equation, from 1 mol of C2H4, 1 mol of C2H5OH is formed. In addition, the yield of the reaction product (C2H5OH) is 70%.

Therefore, the amount of substance C2H5OH:

v (C2H5OH) = v (C2H4) * 0.7 = 0.25 * 0.7 = 0.175 (mol).

Thus, the mass of the resulting ethanol:

m (C2H5OH) = v (C2H5OH) * M (C2H5OH) = 0.175 * 46 = 8.05 (g).