Calculate the mass of ethanol with water required to prepare a 300 g 70 percent alcohol solution.

W (ethanol solution) = m (ethanol) / m (ethanol solution) =
m (ethanol) = 0.7 * 300 = 210 g
m (ethanol solution) = m (ethanol) + m (water) =
m (water) = 300 – 210 = 90 g



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