Calculate the mass of ethyl alcohol that can be obtained by reacting 72.8 liters of ethylene with water.

By the condition of the problem, we write the equation:
Н2С = СН2 + Н2О = Н3С – СН2ОН – ethylene hydration reaction, ethanol was obtained;
Let’s calculate the molar masses of substances:
M (C2H4) = 28 g / mol;
M (C2H5OH) = 46 g / mol.
Let us determine the number of moles of ethylene, if the mass is known:
Y (C2H4) = m / M = 72.8 / 28 = 2.6 mol;
According to the reaction equation, the amount of moles of ethylene and ethyl alcohol is equal to 1 mol, which means that Y (C2H5OH) = 2.6 mol.
We find the mass of ethanol by the formula:
m (C2H5OH) = Y * M = 2.6 * 46 = 119.6 g.
Answer: the mass of ethyl alcohol is 119.6 g.