Calculate the mass of FeCl3 when 30 grams of iron reacts with chlorine.

Given:

m (Fe) = 30 g

To find:

m (FeCl3) -?

Decision:

1) We compose the reaction equation corresponding to the condition of the given problem:

2Fe + 3Cl2 = 2FeCl3

2) Find the amount of iron contained in 30 grams of metal:

n (Fe) = m: M = 30 g: 56 g / mol = 0.54 mol;

3) We compose logical equality:

if 2 mol of Fe gives 2 mol of FeCl3,

then 0.54 mol of Fe will give x mol of FeCl3,

then x = 0.54 mol.

4) Find the mass of ferric chloride formed as a result of the reaction:

m (FeCl3) = n * M = 0.54 mol * 162.5 g / mol = 87.75 g.

Answer: m (FeCl3) = 87.75 g.