Calculate the mass of formic acid obtained by oxidation of 11.2 liters of formaldehyde.

Let’s implement the solution:
1. Let’s make the equation:
НСОН + Ag2O = HCOOH + 2Ag – qualitative reaction to aldehyde, interaction with silver oxide, silver and formic acid are released;
2. Let’s define the molar masses of substances:
M (CH2O) = 12 + 2 + 16 = 30 g / mol;
M (HCOOH) = 2 + 12 + 16 * 2 = 46 g / mol;
3. Let’s calculate the amount of mol of aldehyde:
Y (CH2O) = m / M = 11, 2/30 = 0.37 mol;
4. Let’s make the proportion:
0.37 mol (CH2O) – X mol (HCOOH);
-1 mol -1 mol hence, X mol (HCOOH) = 0.37 * 1/1 = 0.37 mol;
5. Let’s calculate by the formula:
m (HCOOH) = Y * M = 0.37 * 46 = 17 g.
Answer: the mass of formic acid is 17 g.