Calculate the mass of glucose if 440 g of carbon dioxide is released.

To solve, you need to make an equation:
С6Н12О6 + 6О2 = 6СО2 + 6Н2О – the reaction of glucose combustion is accompanied by the release of carbon dioxide;
Let’s calculate the molar masses of substances:
M (C6H12O6) = 180 g / mol;
M (CO2) = 44 g / mol.
Let us determine the amount of moles of carbon dioxide, if the mass is known:
Y (CO2) = m / M = 440/44 = 10 mol.
Let’s make the proportion:
X mol (C6H12O6) – 10 mol (CO2);
– 1 mol                      – 6 mol from here, X mol (C6H12O6) = 1 * 10/6 = 1.66 mol.
We find the mass of glucose:
m (C6H12O6) = Y * M = 1.66 * 180 = 298.8 g.
Answer: the reaction requires glucose weighing 298.8 g.