Calculate the mass of H2, which is formed by interaction with hydrochloric acid, 101.25 kg of aluminum

Calculate the mass of H2, which is formed by interaction with hydrochloric acid, 101.25 kg of aluminum containing 20% impurities.

1. Let’s find the mass of pure aluminum:

101.25 kg Al – 100%

x kg Al – 80%

Hence, x = 101.25 * 80/100 = 81 kg

2. Let’s compose the reaction equation:

2 Al + 6 HCl = 2 AlCl3 + 3 H2

According to the equation:

2 mol of aluminum enters into the reaction;
3 mol of hydrogen is formed.
Let’s find the mass of aluminum by the formula:

m (Al) = n * M = 2 mol * 27 g / mol = 54 g

Let’s find the mass of hydrogen by the formula:

m (H2) = n * M = 3 mol * (1 * 2) = 6 g

3. Let’s calculate the mass of hydrogen, making up the proportion:

81 kg Al – x kg H2

54 g Al – 6 g H2

Hence, x = 81 * 6/54 = 9 kg.