Calculate the mass of hydrogen for the interaction of sodium 24 g with water.

univerkov | January 17, 2021 | education

Given:
m (Na) = 24 g
To find:
m (H2)
Decision:
2Na + 2H2O = 2NaOH + H2
n (Na) = m / M = 24 g / 23 g / mol = 1.04 mol
n (Na): n (H2) = 2: 1
n (H2) = 1.04 mol / 2 = 0.52 mol
m (H2) = n * M = 0.52 mol * 2 g / mol = 1.04 g
Answer: 1.04 g

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