Calculate the mass of iodine displaced by bromine from 0.4 mol of potassium iodide.

Given:
n (KI) = 0.4 mol

To find:
m (I2) -?

1) Br2 + 2KI => 2KBr + I2;
2) n (I2) = n (KI) / 2 = 0.4 / 2 = 0.2 mol;
3) m (I2) = n * M = 0.2 * 254 = 50.8 g.

Answer: The mass of I2 is 50.8 g.



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