Calculate the mass of iron chloride formed during the chlorination of iron weighing 112 g.

Ferric chloride production reaction:
2Fe + 3Cl2 = 2FeCl3.
Find the number of moles of iron:
n = m / Mr = 112/56 = 2 mol.
It can be seen from the reaction equation that the product yield will be the same, i.e. 2 mol.
Find the mass of ferric chloride:
m (FeCl3) = n * Mr = 2 * 162.5 = 325 g.



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