Calculate the mass of iron formed when it is reduced from iron (III) oxide weighing 80 g, if the mass fraction

| September 2, 2021 | education

Calculate the mass of iron formed when it is reduced from iron (III) oxide weighing 80 g, if the mass fraction of the product yield is 80%

1. The reduction of iron from oxide occurs in accordance with the reaction:

Fe2O3 + 3H2 = 2Fe + 3H2O;

2.Considering the product yield, let us establish the practical mass of the reacted oxide:

mpr (Fe2O3) = ν * mtheor (Fe2O3) = 0.8 * 80 = 64 g;

3. Find the chemical amount of iron oxide:

n (Fe2O3) = mpr (Fe2O3): M (Fe2O3);

M (Fe2O3) = 2 * 56 + 3 * 16 = 160 g / mol;

n (Fe2O3) = 64: 160 = 0.4 mol;

4. The amount of iron is twice the amount of oxide, since two units of iron are released from one oxide molecule:

n (Fe) = n (Fe2O3) * 2 = 0.4 * 2 = 0.8 mol;

5. Let’s calculate the mass of iron:

m (Fe) = n (Fe) * M (Fe) = 0.8 * 56 = 44.8 g.

Answer: 44.8 g.



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