Calculate the mass of iron (III) chloride, which is formed by the interaction of hydrochloric acid with 60 grams of iron (III)
| November 24, 2020 | education
Calculate the mass of iron (III) chloride, which is formed by the interaction of hydrochloric acid with 60 grams of iron (III) oxide containing 20% impurities.
Fe2O3 + 6HCl = 2FeCl3 + 3H2O
m (pure Fe2O3) = 60 g * 0.8 = 48 g
n (Fe2O3) = 48 g / 160 g / mol = 0.3 mol
n (FeCl3) = 0.3 mol
m (FeCl3) = 0.3 mol * 162.5 g / mol = 48.75 g
Answer: 48.75 g.
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