Calculate the mass of iron (III) oxide reacted with hydrochloric acid if 6 mol of iron (III) chloride was formed

| March 11, 2021 | education

Calculate the mass of iron (III) oxide reacted with hydrochloric acid if 6 mol of iron (III) chloride was formed as a result of the reaction.

Let us write the equation according to the condition of the problem, select the coefficients:
Fe2O3 + 6HCl = 2FeCl3 + 3H2O – ion exchange reaction, ferric chloride and water were obtained;
Let’s calculate the molar masses of substances according to the equation:
M (Fe2O3) = 159.6 g / mol;
M (FeCl3) = 162.3 g / mol.
According to the equation, we will compose the proportion:
X mol (Fe2O3) – 6 mol (FeCl3);
-1 mol -2 mol from here, X mol (Fe2O3) = 1 * 6/2 = 3 mol.
Find the mass of iron oxide (3) by the formula:
m (Fe2O3) = Y * M = 3 * 159.6 = 478.8 g.
Answer: iron oxide (3) with a mass of 478.8 g enters the reaction.



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