# Calculate the mass of iron oxide 3 obtained by compressing 28 grams of iron in oxygen.

January 13, 2021 | education

| Given:

m (Fe) = 28 g

To find:

m (Fe2O3) -?

Decision:

4Fe + 3O2 = 2Fe2O3, – we solve the problem, relying on the composed reaction equation:

1) Find the amount of iron contained in 28 grams of the substance:

n (Fe) = m: M = 28 g: 56 g / mol = 0.5 mol;

2) We compose a logical expression:

if 2 mol of Fe2O3 requires 4 mol of Fe,

then x mol of Fe2O3 will require 0.05 mol of Fe,

then x = 0.025 mol.

3) Find the mass of iron oxide formed as a result of the reaction:

m (Fe2O3) = n * M = 0.025 mol * 160 g / mol = 4 g.

Answer: m (Fe2O3) = 4 g.

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