Calculate the mass of iron oxide required to obtain 40 g of iron FeO + H2 = Fe + H2O

Given

m (Fe) = 40 g

To find:

m (FeO) -?

Decision:

FeO + H2 = Fe + H2O, – we solve the problem, relying on the composed reaction equation:

1) Find the amount of iron produced during the reaction:

n (Fe) = m: M = 40 g: 56 g / mol = 0.71 mol

2) We compose a logical expression:

If 1 mol of FeO gives 1 mol of Fe, then x mol of FeO gives 0.71 mol of Fe, then x = 0.71 mol.

3) Find the mass of iron oxide required for the reaction to proceed:

m (FeO) = n * M = 0.71 mol * 72 g / mol = 51.12 g.

Answer: m (FeO) = 51.12 g.