Calculate the mass of iron required to form 11.8 liters. hydrogen: Fe + H2SO4 → FeSO4 + H2

1. Let us find the amount of the substance of hydrogen by the formula v = V / 22.4, where v is the amount of the substance, V is the volume of the substance, 22.4 l / mol is the molar volume of gases.

v = 11.8 / 22.4 = 0.527 mol

2. The reaction equation shows that all substances are in an equimolar ratio (the coefficient in front of all substances is equal to one). This means that the amount of iron is equal to the amount of hydrogen.

v (H2) = v (Fe) = 0.527 mol

3. Let us find the mass of iron by the formula m = Mr * v, where m is the mass of the substance, Mr is the molecular mass.

Mr (Fe) = 55.85 g / mol

m (Fe) = 55.85 * 0.527 = 29.43 g

Answer: 29.43 g of iron is needed to form 11.8 liters of hydrogen.