Calculate the mass of iron required to obtain 200 g of iron oxide Fe3O4.

univerkov | December 19, 2020 | education

Given:
m (Fe3O4) = 200 g
To find:
m (Fe) -?
Decision.
3Fe + 2O2 = Fe3O4
n (Fe3O4) = m (Fe3O4) / M (Fe3O4) = 200/232 = 0.86 mol
n (Fe) = n (Fe3O4) / 3 = 0.86 / 3 = 0.29 mol
m (Fe) = M (Fe) * n (Fe) = 56 * 0.29 = 16.24 g
Answer: 16.24 g.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.