Calculate the mass of iron sulfide (2) obtained by the reaction of 0.1 mol of iron with sulfur.

Given:
n (Fe) = 0.1 mol

To find:
m (FeS) -?

Decision:
1) Fe + S => FeS;
2) n (FeS) = n (Fe) = 0.1 mol;
3) m (FeS) = n (FeS) * M (FeS) = 0.1 * 88 = 8.8 g.

Answer: The FeS mass is 8.8 g.



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