Calculate the mass of iron that can be obtained by the interaction of iron oxide (3) weighing 50 g

Calculate the mass of iron that can be obtained by the interaction of iron oxide (3) weighing 50 g with aluminum if the mass fraction of the product yield is 92%

Given:

m (Fe2O3) = 50 g

w% (Fe practical) = 92%

To find:

m (Fe) -?

Decision:

Fe2O3 + 2Al = Al2O3 + 2Fe, – we use the composed reaction equation to solve the problem:

1) Find the amount of iron oxide contained in 50 grams of the substance:

n (Fe2O3) = m: M = 50 g: 160 g / mol = 0.3125 mol;

2) We compose a logical expression:

if 1 mol of Fe2O3 gives 2 mol of Fe,

then 0.3125 mol of Fe2O3 will give x mol of Fe,

then x = 0.625 mol.

3) Find the theoretically possible mass of iron yield:

m (Fe) = n * M = 0.625 mol * 56 g / mol = 35 g;

4) We find a practical output of iron:

m (Fe) = 35 g * 0.92 = 32.2 g.

Answer: m (Fe) = 32.2 g.