Calculate the mass of iron that can be obtained from 160 g of iron (III) oxide, containing 10%

| August 14, 2021 | education

Calculate the mass of iron that can be obtained from 160 g of iron (III) oxide, containing 10% impurities, when it is reduced with carbon.

1. Let’s find the mass of pure iron oxide without impurities.

100% – 10% = 90%.

160 g – 100%,

X – 90%,

X = (160g × 90%): 100% = 144g.

Find the amount of iron (III) oxide substance by the formula:
n = m: M.

M (Fe2O3) = 56 × 2 + 16 × 3 = 160 g / mol.

n = 144 g: 160 g / mol = 0.9 mol.

We compose the reaction equation. We determine in what quantitative ratios the substances are.
Fe2O3 + 3CO = 2Fe + 3CO2.

There are 2 moles of iron per mole of iron oxide. Substances are in quantitative ratios of 1: 2.
The amount of the iron substance will be 2 times more than the amount of the iron oxide substance.

n (Fe) = 0.9 × 2 = 1.8 mol.

Let’s find the mass of iron by the formula:

m = n × M,

M (Fe) = 56 g / mol.

m = 1.8 mol × 56 g / mol = 100.8 g.

Answer: 100.8g.



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