Calculate the mass of iron that can be obtained from 36g of iron (II) oxide.

Iron oxide decomposes at a tremendous temperature of over 1500 degrees, while forming oxygen and metallic iron: 2FeO = 2Fe + O2 – two moles of iron oxide give two moles of metallic iron. Below, under the iron oxide, write the mass of the compound = 144 grams, above this compound, write 36 grams (the mass is given in the problem statement). Now, below under the iron (metal) we write its mass = 112 grams, and above the iron we write X. Hence, X = 36 * 112/144 = 28 grams. The mass of iron that can be obtained from 36 g of iron (II) oxide is 28 grams.