Calculate the mass of iron that can be obtained from 36g of iron (II) oxide.

Given:
m (FeO) = 36 g

To find:
m (Fe) -?

1) Write the reaction equation:
FeO + CO => Fe + CO2;
2) Calculate the molar mass of FeO:
M (FeO) = Mr (FeO) = Ar (Fe) * N (Fe) + Ar (O) * N (O) = 56 * 1 + 16 * 1 = 72 g / mol;
3) Calculate the amount of FeO:
n (FeO) = m (FeO) / M (FeO) = 36/72 = 0.5 mol;
4) Determine the amount of Fe substance:
n (Fe) = n (FeO) = 0.5 mol;
5) Determine the molar mass of Fe:
M (Fe) = Ar (Fe) = 56 g / mol;
6) Calculate the mass of Fe:
m (Fe) = n (Fe) * M (Fe) = 0.5 * 56 = 28 g.

Answer: The mass of Fe is 28 g.