Calculate the mass of iron that can be obtained with 4 kg of iron (III) oxide.

Given:
m (Fe2O3) = 4kg = 4000g
To find:
m (Fe) =? kg
Decision:
2Fe2O3 = 4Fe + 3O2
M (2Fe2O3) = 2 (112 + 48) = 320 g / mol
M (4Fe) = 4 * 56 = 224 g / mol
4000/320 = x / 224
x = (4000 * 224) / 320 = 2800g
Answer. m (Fe) = 2800g = 2.8kg



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