Calculate the mass of iron, which can be obtained from 480 g of iron oxide (3) when reducing it with carbon monoxide (2)

Calculate the mass of iron, which can be obtained from 480 g of iron oxide (3) when reducing it with carbon monoxide (2), if the mass fraction of the yield of iron is 95%

Let’s find the amount of the substance of iron oxide (III) Fe2O3 by the formula:
n = m: M.
M (Fe2O3) = 56 × 2 + 16 × 3 = 160 g / mol.
n = 480 g: 160 g / mol = 3 mol.
Let’s compose the reaction equation, find the quantitative ratios of substances.
Fe2O3 + 3CO = 2Fe + 3CO2
According to the reaction equation, there is 2 mol of iron per 1 mole of iron oxide. The substances are in quantitative ratios of 1: 2.
The amount of the iron substance will be 2 times more than the amount of the iron oxide substance.
n (Fe) = 1 / 2n (Fe2O3) = 3 mol: 2 = 1.5 mol.
Find the mass of iron by the formula:
m = n × M,
M (Fe) = 56 g / mol.
m = 1.5 mol × 56 g / mol = 84 g.
84 g was calculated (theoretical yield).
According to the condition of the problem, the iron yield is 95%.
Let’s find a practical way out of the product.
84 g – 100%,
x g – 95%,
x = (84 × 95%): 100% = 79.8 g.
Answer: 79.8 g.