Calculate the mass of iron, which corresponds to 48 * 10²³ iron atoms.
March 30, 2021 | education
| 1. find the chemical amount of iron:
n (Fe) = N (Fe): Na, where Na is Avogadro’s constant and Na = 6.02 * 10 ^ 23 mol-1;
n (Fe) = 48 * 10 ^ 23: 6.02 * 10 ^ 23 = 7.97 mol;
2.Knowing the amount, we find the mass of a portion of iron:
m (Fe) = n (Fe) * M (Fe) = 7.97 * 56 = 446.32 g.
Answer: 446.32 g.
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