Calculate the mass of iron with a mass fraction of iron of 95.4%, which can be obtained

Calculate the mass of iron with a mass fraction of iron of 95.4%, which can be obtained from Fe3O4 with a mass of 320 tons, if the production loss is 6.2%.

2 12Fe3O4 + 4C = 4CO2 + 6Fe
2Fe2O3 + 3C = 3CO2 + 4Fe
1 n (CO2) = 0.672 / 22.4 = 0.03 mol
n (CO2) / 2 = n (Fe3O4) = 0.3 / 2 = 0.015 mol
M (Fe3O4) = 1.6 / 0.15 = 106.7 g / mol
Fe3O4 is not suitable, since M (Fe3O4) = 232 g / mol
2 n (CO2) = 0.672 / 22.4 = 0.03 mol
n (Fe2O3) = 0.03 / 3 = 0.01 mol
M (Fe2O3) = 1.6 / 0.01 = 160 g / mol
Fe2O3 is suitable since its M (Fe2O3) = 160 g / mol