Calculate the mass of magnesium dissolved in hydrochloric acid, if at the same time hydrogen

Calculate the mass of magnesium dissolved in hydrochloric acid, if at the same time hydrogen is evolved with a volume of 4.48 liters.

Let’s implement the solution:
1. We make the equation:
X g -? V = 4.48 liters.
Mg + 2HCl = MgCl2 + H2 – OBP, hydrogen, magnesium chloride are evolved;
2. Calculations:
M (Mg) = 24.3 g / mol.
M (H2) = 2 g / mol.
3. Proportion:
1 mol of gas at normal level – 22.4 liters;
X mol (H2) – 4.48 liters. hence, X mol (H2) = 1 * 4.48 / 22.4 = 0.2 mol.
Y (Mg) = 0.2 mol since the amount of substances according to the equation is 1 mol.
4. Find the mass of the metal Mg:
m (Mg) = Y * M = 0.2 * 24.3 = 4.86 g.
Answer: you need magnesium weighing 4.86 g.